2x^2-46x-3696=0

Solution for 2x^2-46x-3696=0 equation:

2x^2-46x-3696=0

a = 2; b = -46; c = -3696;
Δ = b2-4ac
Δ = -462-4·2·(-3696)
Δ = 31684
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{31684}=178$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-178}{2*2}=\frac{-132}{4}
=-33
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+178}{2*2}=\frac{224}{4}
=56
$